| 這個program的效果是確認在9*9的方格中，在同一個橫排、直排和3*3的方格中的數值沒有相同﹕
#include <stdio.h>
int main(){
int num[9][9], row, column, i, j, k, l, temp, check, min[3] = {0, 3, 6}, max[3] = {3, 6, 9};
for (row = 0; row < 9; row++){
for (column = 0; column < 9; column++){
do{
check = 0;
printf("Input the number at (%d,%d):", row + 1, column + 1);
scanf("%d", &num[row][column]);
temp = num[row][column];
if (num[row][column] < 0 || num[row][column] > 9){
printf("Input Error!\n");
check = 1;}
for (i = 0; i < column; i++)
if (temp == num[row][ i]){
printf("Same number on the same column!\n");
check = 1;}
for (i = 0; i < row; i++)
if (temp == num[ i][column]){
printf("Same number on the same row!\n");
check = 1;}
if (row < 3)
i = 0;
else if (row < 6)
i = 1;
else
i = 2;
if (column < 3)
j = 0;
else if (column < 6)
j = 1;
else
j = 2;
for (k = min[ i]; k < max[ i]; k++)
for (l = min[j]; l < max[j]; l++)
if (k != row || l != column)
if (temp == num[k][l]){
printf("Same number in the same square!\n");
check = 1;}}
while(check);}}
if (!check)
printf("You win!\n");
for (row = 0; row < 9;row++){
for (column = 0; column < 9; column++)
printf("%4d", num[row][column]);
printf("\n");}
system("Pause");
return 0;}
2 6 5 1 7 3 4 8 9
1 8 3 5 4 9 7 2 6
7 9 4 2 8 6 5 1 3
4 1 8 3 9 7 2 6 5
9 2 7 6 5 8 3 4 1
5 3 6 4 1 2 9 7 8
8 5 1 7 3 4 6 9 2
3 4 2 9 6 1 8 5 7
6 7 9 8 2 5 1 3 4
事後證明num[ i][j](i = 0-1, j = 3-8; i = 3-5, j = 3-5)也會因以上理由而不接納"2"的輸入。
(num[5][6]以後的變數難以證明)
認為用來確認3*3方格內數值的部分﹕
if (row < 3)
i = 0;
else if (row < 6)
i = 1;
else
i = 2;
if (column < 3)
j = 0;
else if (column < 6)
j = 1;
else
j = 2;
for (k = min[ i]; k < max[ i]; k++)
for (l = min[j]; l < max[j]; l++)
if (k != row || l != column)
if (temp == num[k][l]){
printf("Same number in the same square!\n");
check = 1;}
有誤，請問各位有關問題的錯誤原因和修正方法。
[ 本帖最後由 魔術師Chikorita 於 26/4/2008 10:52 PM 編輯 ] |
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發表於 26/4/2008 01:34 AM 
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發表於 26/4/2008 08:47 PM 
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