本帖最後由 Ivanhy92 於 5/10/2011 07:46 PM 編輯 a) For sinosoidal signal, V[peak] = sqrt2 V[rms] Hence, V(t) = V[peak] sin(ωt) = sqrt2 V[rms] sin(2πf t) (since ω=2πf ) = 110sqrt2 sin(120πt) b) (懷疑DSE out-syl.?) Since V[across R] is in phase with I[across R], and V=IR by Ohm's Law, P(t) = V(t)I(t) = [V(t)]^2/R =[110sqrt2 sin(120πt)]^2/R =1210 sin^2(120πt) P(2x10^-3) = ...... |