唔識計@___________@

鴨

Originally posted by Kimo at 2005-10-30 05:09 PM:

我也只是F.1而已...樓主跟我同年的
不過唔知點解我maths特別勁，P.2開始年年maths全級第一(晒

知你叻啦...唔駛係度曬....

Originally posted by 可愛的兔兒 at 2005-10-30 06:47 PM:
只是比較複雜的代入問題吧......

死囉...我F.3都唔係好明....

sing1993

Originally posted by 路人2號 at 2005-10-30 17:03:

你們教的真快.....
我們現在才做到9b.....T.Tlll

nono.....上次咩鬼測驗果d...=.=

路人2號

Originally posted by sing1993 at 2005-11-7 07:32 PM:

nono.....上次咩鬼測驗果d...=.=

我們班測驗好像沒有測到這些膠東東喔xddd.....

碧咸

三條equation
三個unknown
要solve實得

宇文水靈

No need to be so trouble. I have an easy way to do!!!
x>0
x(y+z)=5
y(x+z)=10
z(x+y)=13
xy + xz = 5
xy + yz = 10
xz + yz = 13
Let a=xy, b=yz, c=xz.
a+c=5----------------------------(1)
a+b=10--------------------------(2)
b+c=13--------------------------(3)
(2) - (1) b-c=5----------------(4)
(3) + (4)  2b=18
                b=9
From equation (3), c=4
From equation (1), a=1
We have xy=1, --------------------(5)
             yz=9, --------------------(6)
             xz=4  --------------------(7)
From equation (5), x=1/y------(8)
Put (8) into (7), z/y=4
                         z=4y----------(9)
Put (9) into (6), 4y^2=9
                             y= +-3/2---(10)
Put (10) into (8), x= +-2/3
Since x > 0, x= -2/3 and y= -3/2 have to be rejected.
Therefore, x=2/3 and y=3/2
Put y = 3/2 into (9), z=6
Overall, x=2/3
           y=3/2
           z=6