Originally posted by 紅唇娃 at 2005-3-5 11:51 PM: 1b 3角形中間係個diameter, 即係ABD係 isoceles (差唔多啦) triangle. 即係BE=DE, 所以BC=CD 2 AB=BC, across diameter and center, therefore, A and C have the same distance from B and O. AB=CB, AO=CO ... 1b
i don't understand... question 2 also....... ================================ my answer: 1b
if triangle ABE and triangle ADE are 全等(forget jor the English term), angle BAE = angle DAE therefore, arc BC = arc CD (arc prop. to angles at circumference) Question 2 similar to 1 b prove the two triangle are 全等(SSS) then use property PS: but the property is not (arc prop. to angles at circumference) it is (arcs prop. to angles at centre) [ Last edited by smallpotato226 on 2005-3-6 at 04:57 PM ] |