我的方法,不知和你的是否一樣 (或許比你的更慢卅▽卅) Since H is orthocentre of △ABC, ∠AOC=90° ∠BCS=90° (∠ in semi-circle) ∠AOC+∠BCS=180° ∴AH//SC Produce CH and meet at AB. Let Z be their intersection. Since H is orthocentre of △ABC, ∠AZC=90° ∠AZC=∠SCB ∠ZAC=∠CSB (∠s in same seg.) ∴△AZC~△SCA (AA) ∠ACZ=∠SBC (corr. ∠s, ~△s) ∠SAC=∠SBC (∠s in same seg.) ∠SAC=∠ACZ ∴AS//HC Since AS//HC and AH//SC, AHCS is a //gram. |