Let the line be y=mx+c The line pass through (1,0). Put (1,0) into the eqt. 0=m+c m=-c ∴The eqt becomes y=m(x-1) put y=m(x-1) into y^2=4x (m^2)(x-1)^2=4x (mx)^2-2(m^2+2)x+A^2=0 ------(1) Let the mid-pt P be (x1,y1) x1=sum of roots of (1) * 1/2=(m^2+2)/m^2 put x1 into y=m(x-1) y1=2/m m=2/(y1) put m into x1, the required eqt. is y^2=2x-2 |