Originally posted by 紅唇娃 at 2005-3-5 11:51 PM:
1b 3角形中間係個diameter, 即係ABD係 isoceles (差唔多啦) triangle. 即係BE=DE, 所以BC=CD
2 AB=BC, across diameter and center, therefore, A and C have the same distance from B and O. AB=CB, AO=CO
...
BE=DE, 所以BC=CD
if triangle ABE and triangle ADE are 全等(forget jor the English term),
angle BAE = angle DAE
therefore, arc BC = arc CD (arc prop. to angles at circumference)
Originally posted by 紅唇娃 at 2005-3-6 07:55 PM:
BE同DE ge距離一樣﹐因為係等腰3角型
Originally posted by smallpotato226 at 2005-3-7 01:56 PM:
但這樣可以證明BC=CD 的嗎?
Originally posted by smallpotato226 at 2005-3-8 10:38 AM:
haha
都係唔明XD
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