香港寵物小精靈村落論壇

標題: remainder theorem [打印本頁]

作者: 小霞的fans 時間: 3/3/2010 02:47 PM
標題: remainder theorem
when a polynomial P(x) is divided by x-k, the quotient is x+4 and the remainder is 3.when P(x) is divided by x-2k , the remainder is 9. find the possible values of k .

唔係太識點做 t^t "" 希望有人教教我 .. 代x=k 嗎??

作者: sapphire 時間: 3/3/2010 03:01 PM
1. When a polynomial P(x) is divided by x-k, the quotient is x+4 and the remainder is 3.

which implies
P(x) = (x - k)(x + 4) + 3
After calculation, P(x) = x^2 + (4 - k)x - 4k + 3

2. When P(x) is divided by x-2k , the remainder is 9.

which implies
P(2k) = (2k)^2 + (4 - k)(2k) - 4k + 3 = 9

For the rest, it is only a quadratic equation.

Ans : k = 1 or -3

作者: 小霞的fans 時間: 3/3/2010 04:01 PM

1. When a polynomial P(x) is divided by x-k, the quotient is x+4 and the remainder is 3.

which implies
P(x) = (x - k)(x + 4) + 3
After calculation, P(x) = x^2 + (4 - k)x - 4k + 3

2. When P(x) ...
sapphire 發表於 2/3/2010 07:01 PM

登錄/註冊後可看大圖

仲有1題variation我想問@@..

y^2 varies directly as x^2

咁應該寫成y^2=kx^2定係y^2=k^2x^2 ??

作者: unlock-YM 時間: 3/3/2010 04:45 PM

仲有1題variation我想問@@..

y^2 varies directly as x^2

咁應該寫成y^2=kx^2定係y^2=k^2x^2 ??
小霞的fans 發表於 3/3/2010 04:01 PM

登錄/註冊後可看大圖

理論上兩個都冇所謂，反正k只係constant。
實際上你寫 y^2 = kx^2 已經得，無謂畫蛇添足。

作者: Ivanhy92 時間: 3/3/2010 08:06 PM

理論上兩個都冇所謂，反正k只係constant。
實際上你寫 y^2 = kx^2 已經得，無謂畫蛇添足。
unlock-YM 發表於 3-3-2010 16:45

登錄/註冊後可看大圖

y^2 = k x^2 (y^2 is DIRECTLY proportional to x^2)
y^2 = k^2 x^2 (y^2 is EXPONENTIALLY proportional to x^2)

作者: unlock-YM 時間: 3/3/2010 08:36 PM

y^2 = k x^2 (y^2 is DIRECTLY proportional to x^2)
y^2 = k^2 x^2 (y^2 is EXPONENTIALLY proportional to x^2)
arararchchch 發表於 3/3/2010 08:06 PM

登錄/註冊後可看大圖

Are you sure?

歡迎光臨香港寵物小精靈村落論壇 (https://proxy.archiver.hkpnve.pokebeacon.com/)

香港寵物小精靈村落 論壇

香港寵物小精靈村落論壇