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作者: 水龍蜥    時間: 11/9/2007 06:31 PM
標題: 一元二次
2x^2+2p=(4p+1)x
求p,使公式有equal real roots
教下我ok?
作者: sapphire    時間: 11/9/2007 07:24 PM
hv u learn the eqt. D=b^2-4ac yet? in fact this question is extremely easy after u learn this.

2x^2+2p=(4p+1)x
2x^2-(4p+1)x+2p=0  which is a quad. eqt. in x

the eqt. has equal real root if and only if D=0
(4p+1)^2-4(2)(2p)=0
solve the quad. eqt. , u will get the ans p=1/4
作者: 水龍蜥    時間: 11/9/2007 08:48 PM
原帖由 sapphire 於 11/9/2007 07:24 PM 發表
hv u learn the eqt. D=b^2-4ac yet? in fact this question is extremely easy after u learn this.

2x^2+2p=(4p+1)x
2x^2-(4p+1)x+2p=0  which is a quad. eqt. in x

the eqt. has equal real root if and  ...

忘記了用交叉法..難怪計不到
作者: ccshong28    時間: 11/9/2007 09:38 PM
原帖由 水龍蜥 於 11/9/2007 08:48 PM 發表

忘記了用交叉法..難怪計不到

我係F.2既,想問下咩係交叉法= ='
我係咁諗既:
2x^2+2p=(4p+1)x
2x^2=4px+x-2p
2x^2-x=4px-2p
x(2x-1)=2p(2x-1)
x=2p

When x=2p,
2x^2+2p=(4p+1)x
2(2p)^2+2p=(4p+1)x
4p^2+4p^2+2p=(4p+1)x
4p^2+4p^2+2p=(2p+1)(2p)
4p^2+4p^2+2p=4p^2+2p
4p^2=2p
2p=1
p=1/2

我有冇計錯= ='

[ 本帖最後由 ccshong28 於 11/9/2007 09:39 PM 編輯 ]
作者: K龍    時間: 11/9/2007 09:46 PM
原帖由 ccshong28 於 11/9/2007 09:38 PM 發表

我係F.2既,想問下咩係交叉法= ='
我係咁諗既:
2x^2+2p=(4p+1)x
2x^2=4px+x-2p
2x^2-x=4px-2p
x(2x-1)=2p(2x-1)
x=2p

When x=2p,
2x^2+2p=(4p+1)x
2(2p)^2+2p=(4p+1)x
4p^2+4p^2+2p=(4p+1)x
4p^2+4 ...

when x = 2p
2x^2 + 2p = (4p + 1)x
2(2p)^2 + 2p = (4p + 1)(2p)
2(4p^2) + 2p = 8p^2 + 2p
8p^2 + 2p = 8p^2 + 2p
結果是什麼也沒得出

要活用"have equal real root"這info,一般來就都是都以求D的方法去計
作者: sapphire    時間: 11/9/2007 10:24 PM
apart from the reply above
2x^2-x=4px-2p
x(2x-1)=2p(2x-1)
x=2p

here u should not divide both sides by (2x-1)
always remember that u should not divide both sides by a number with an unknown as the number divided may equal to zero

[ 本帖最後由 sapphire 於 11/9/2007 10:31 PM 編輯 ]
作者: ccshong28    時間: 12/9/2007 06:12 PM
原帖由 sapphire 於 11/9/2007 10:24 PM 發表
apart from the reply above

here u should not divide both sides by (2x-1)
always remember that u should not divide both sides by a number with an unknown as the number divided may equal to zero


翻參考書,明白了
thx~^^




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