原帖由 sapphire 於 11/9/2007 07:24 PM 發表
hv u learn the eqt. D=b^2-4ac yet? in fact this question is extremely easy after u learn this.
2x^2+2p=(4p+1)x
2x^2-(4p+1)x+2p=0 which is a quad. eqt. in x
the eqt. has equal real root if and ...
原帖由 ccshong28 於 11/9/2007 09:38 PM 發表
我係F.2既,想問下咩係交叉法= ='
我係咁諗既:
2x^2+2p=(4p+1)x
2x^2=4px+x-2p
2x^2-x=4px-2p
x(2x-1)=2p(2x-1)
x=2p
When x=2p,
2x^2+2p=(4p+1)x
2(2p)^2+2p=(4p+1)x
4p^2+4p^2+2p=(4p+1)x
4p^2+4 ...
2x^2-x=4px-2p
x(2x-1)=2p(2x-1)
x=2p
原帖由 sapphire 於 11/9/2007 10:24 PM 發表
apart from the reply above
here u should not divide both sides by (2x-1)
always remember that u should not divide both sides by a number with an unknown as the number divided may equal to zero
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