原帖由 木守宮的蛙糧-PA 於 26/8/2007 02:46 PM 發表
Solve the equation (x+1)(x-3)=12
(x+1)(x-3)=12
x^2-3x+x-3=12
x^2-2x-3=12
x^2-2x-3-12=0
x^2-2x-15=0
(x-5)(x+3)=0
If x-5=0, then x=5
If x+3=0, then x=-3
∴x=-3 or 5
我想問x^2-2x-15=0為 ...
歡迎光臨 香港寵物小精靈村落 論壇 (https://proxy.archiver.hkpnve.pokebeacon.com/) | Powered by Discuz! X3.2 |